[" Q.If the inverse of "P(-3,5)" w.r.t to a circle is "],[28quad (1,3)" then polar of "P" w.r.t to the circle is "]

If the inverse of P(-3,5) w.r.t to a circle is (1,3) then polar of P w.r.t to the circle is

If the inverse of P(-3,5) w.r.t to a circle is (1,3) then polar of P w.r.t to the circle is

If the inverse of P(−3,5) w.r.t to a circle is (1,3) then polar of P w.r.t to the circle is a) x+2y=7 b) 2x-2y+11=0 c) 2x-y+1=0 d) 2x-y-1=0

The polars of two points A(1,3), B(2,-1) w.r.t to circle x^(2)+y^(2)=9 intersect at C then polar of C w.r.t to the circle is

The polars of two points A(1,3), B(2,-1) w.r.t to circle x^(2)+y^(2)=9 intersect at C then polar of C w.r.t to the circle is

Image of (2,3) w.r.t to (-1,3) is

The inverse point of P(4,3) W.r.t the circle x^(2)+y^(2)=25 is

The inverse point of (1,2) w.r.t. the circle x^(2)+y^(2)=25 , is (5,k) then k=

The inverse point of (1,2) w.r.t. the circle x^(2)+y^(2)=25 , is (5,k) then k=

Find the polar of the point (1,2) w.r.t the circle x^2+y^2=7 .