Evaluate int2log(secx+tanx)secxdx....

Evaluate `int2log(secx+tanx)secxdx.`

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The correct Answer is:

`secxdx`

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NEW JOYTHI PUBLICATION-INTEGRALS -OBJECTIVE TYPE QUESTIONS

Evaluate int2log(secx+tanx)secxdx.
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inte^(alogx)dx is equal to
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intsec^(2)(7+4x)dx equal to
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int2x.e^(x^(2))dx equal to
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intcos^(3)x.e^(logsinx)dx is equal to
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int(e^(alogx)+e^(xloga))dx is equal to
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int(sin^(2)x)/(cos^(4)x)dx=
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int13^(x)dx
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inte^(-logx)dx=?
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int(1)/(x^(2)+4x+13)dx is equal to
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int(f'(x))/(f(x)log{f(x)})dx=
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The value of int(e^(5log(e)x)+e^(4log(e)x))/(e^(3log(e)x)+e^(2log(e)x)...
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int(1)/(x(logx)log(logx))dx=
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int(cos^(-1)x+sin^(-1)x)dx is equal to
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intsqrt(x^(2)+a^(2))dx is equal to
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intxdx is equal to
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intsin^(-1)xdx
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If intsinx(d)/(dx)("sec x")dx=f(x)-g(x)+C , then
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int2e^(x){logsinx+cotx}dx=
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inte^(x)(sinx+2cosx)sinxdx is equal to
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int(e^(x))/(x)(1+xlogx)dx is equal to
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