Consider the parabola `y^(2) = 4ax` (i) Write the equation of the rectum and obtain the x co-ordinates of the point of intersection of latus rectum and the parabola. (ii) Find the area of the parabola bounded by the latus rectum.
Text Solution
Verified by Experts
The correct Answer is:
(ii)`(8)/(3)a^(2)` sq.unit
Topper's Solved these Questions
APPLICATION OF INTEGRALS
NEW JOYTHI PUBLICATION|Exercise NCERT TEXT BOOK EXERCISE 8.1|13 Videos
APPLICATION OF INTEGRALS
NEW JOYTHI PUBLICATION|Exercise NCERT TEXT BOOK EXERCISE 8.2|7 Videos
BINOMIAL THEOREM
NEW JOYTHI PUBLICATION|Exercise QUESTIONS FROM COMPETITIVE EXAMS|51 Videos
Similar Questions
Explore conceptually related problems
Find the area of the parabola y^2=4ax and its latus rectum.
The locus of the point of intersection of perependicular tangent of the parabola y^(2) =4ax is
The latus rectum of the parabola y^2 = 11x is of length
Find the length of the Latus rectum of the parabola y^(2)=4ax .
Find the coordinates of the focus , axis, the equation of the directrix and latus rectum of the parabola y^(2)=8x .
The area bounded by the parabola x^2=y and is latus rectum is :
The area bounded by the parabola y^(2) = x and its latus rectum is
The latus rectum of the parabola y^(2)-4x+4y+8=0 is:
NEW JOYTHI PUBLICATION-APPLICATION OF INTEGRALS-CONTINUOUS EVALUATION (LAB Work )
