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Suppose that 90% of people are right- ha...

Suppose that 90% of people are right- handed. What is the probability that atmost 6 of a random sample of 10 people are right- handed?

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The correct Answer is:
`1-sum_(r=7)^10""^(10)C_(r)((9)/(10))^(r)((1)/(10))^(10-r)`
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NEW JOYTHI PUBLICATION-PROBABILITY-SOLUTIONS TO NCERT MISCELLANEOUS EXERCISE
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