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If A and B are any two events then P(bar...

If A and B are any two events then `P(barAnnB) =`

A

`P(barA).P(barB)`

B

1- P(A)P(B)

C

`P(A)+ P(B)- P(A nn B)`

D

`P(B)- P(A nn B)`

Text Solution

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The correct Answer is:
D
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