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A cirular coil of wire cansiting of 100 ...

A cirular coil of wire cansiting of 100 turns ,each of readius 8.0 cm carries a current of 0.40 A. What is the magnitude of the magnetic field `barB` at the centre of the coil ?

Text Solution

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`n= 100 ,I=0.40 A, r= 8.0 cm = 8.0 xx 10^(-2) m`
`B = (mu_0nl )/(2r) = (4pi xx 10^(-7) xx 100 xx 0.4 )/(2xx8xx10^(-2))= pi xx 10^(-4) T`
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