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A flat search coil of 100 turns and each...

A flat search coil of 100 turns and each of area `3xx10^(-4)m^(2)` is connected to a galvanometer, so that the total resistance of the circuit is `90Omega`. The plane of the coil is normal to a magnetic field, B = 0.4T. Calculate the change in flux when the coil is moved to a region of negligible magnetic field and the charge passes through the galvanometer.

Text Solution

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`A=3xx10^(-4)m^(2),N=100,R=90Omega,B=0.4T`
Magnetic flux `(phi_(B))=NAB=100xx3xx10^(-4)xx0.4=1.2xx10^(-2)` weber
`phi_(B)=1.2xx10^(-2),phi_(B)=0`
`therefore` Charge `Q=(phi_(B)-phi_(B).)/(R)=(1.2xx10^(-2))/(90)=1.33xx10^(-4)C`
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