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A light bulb is at 100 W for a 220 V sup...

A light bulb is at 100 W for a 220 V supply . Find (a) the resistance of the bulb , (b) the peak voltage of the source , and (c ) the rms current through the bulb.

Text Solution

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a. We are given P = 100 W and V = 220V. The resistance of the bulb is
`R = (V^2)/(P) = ((220)^2)/(100) = 484 Omega`
b. The peak voltage of the source is `v_m =sqrt2 V = 311 V`
c . Since P = IV
`I = P/V = 100/220 = 0.450 A`
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