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A pure inductor of 25.0 mH is connected ...

A pure inductor of 25.0 mH is connected to a source of 220V . Find the inductive reactance and rms current in the circuit if the frequency of the source is 50 Hz .

Text Solution

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`X_L = 2pi v L = 2 xx 3.14 xx 50 xx 25 xx 10^(-3) W = 7.8 Omega`
The rms current in the circuit is `I = (V)/(X_L) = (220V)/(7.85 Omega) = 28A`
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