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A 100muF capacitor in series with a 40Om...

A `100muF` capacitor in series with a `40Omega` resistance is connected to 110 V, 60 Hz supply .
a. What is the maximum current in the circuit ?
b. What is the time lag between the current maximum and the voltage maximum ?

Text Solution

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Data supplied `C = 100 mu F, R = 40 Omega , E_(rms) = 110 V , v = 69Hz`
` E_0 = E_(rms) xx sqrt(2) = 110 xx 1.414 = 155.6 V`
a. ` i_m (E_0)/(Z) = (E_0)/(sqrt(R^2 + ( (1)/(omega C) )^2)) = (155.6 )/(sqrt(40^2 + ( (1)/(10^(-4) xx 2 xx 3.14 xx 69) )^2) ) = 3.242 A`
b. ` tan phi = (1)/(omega CR)`
` tan phi = (1)/(10^(-4) xx 2 xx 3.14 xx 69 xx 40) = 0.6635`
`phi = tan^(-1) (0.6635) = 30.11^@ = 30^@ = (30 xx pi)/(180) = pi/6`
`phi = omega t , t = phi/omega = (pi)/(6 xx 2 xx pi xx 69) = 1.21 xx 10^(-3) s = 1.21 ms `
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