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A 2muF capacitor is charged to a p.d. o...

`A 2muF` capacitor is charged to a p.d. of 60V. The charging battery is disconnected and the capacitor is connected in series with a coil of inductance 10mH, so that LC oscillations occur. What is the maximum current in the coil? Assume that the circuit contains no resistance.

Text Solution

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`C = 2 xx 10^(-6) F , L = 10 xx 10^(-3) H, V = 60 V`
` (Li_m^2) /(2) = (Q^2)/(2C)`
` i_m = sqrt( (Q^2)/(LC) )`
But Q = CV
`therefore i_m = sqrt( (C^2V^2)/(LC) ) = sqrt( (CV^2)/(L) )`
` therefore = i_m = sqrt( (C^2 V^2)/(LC) ) = sqrt( (CV^2)/(L) ) = sqrt( (2 xx 10^(-6) xx 60 xx 60 )/(10 xx 10^(-3) ) ) =6 sqrt(2 xx 10^(-2) ) = 0.848 A = 848 mA`
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