In a transformer primary has 50 turns and secondary has 10 turns . The RMS voltage in the primary is 120V . Find the RMS secondary voltage in the open circuit .if the secondary has a load of `12 Omega` . What are the currents in the primary and secondary ?

Explanation

`V_S/V_P = N_S/N_P = I_P/I_S`
`N_P = 500 , N_S = 10 , V_P = 120 V`
` therefore V_S = N_S/N_P xx V_P = 10/500 xx 120 = 2.4 V`
by the ohm.s law current in the secondary
`I_S = V_S/R_S = (2.4)/(12) = 0.2A`
Hence current in the primary
`I_P = N_S/N_P xx I_S = 10/500 xx 0.2 = 4 xx 10^(-3) A `
`I_P = 4mA`