A `100muF` capacitor in series with a `40Omega` resistance is connected to 110 V, 60 Hz supply .
a. What is the maximum current in the circuit ?
b. What is the time lag between the current maximum and the voltage maximum ?

Explanation

a. `I_(rms) = (E_(rms) )/(sqrt(R^2 + ( (1)/(2pi v C) )^2)) = (110 sqrt2)/(sqrt((40)^2 + (1)/((2pi xx 60 xx 100 xx 10^(-6) )^2) ) ) = 3.23 A`
`tan phi = (-X_C)/(R ) = (-1)/(2pi v C R) = (-1)/(2pi xx 60 xx 100 xx 10^(-6) xx 40) = - 0.6631 ` (-ve sign shown that current leads voltage ) ` therefore |phi| = 33.5^@`
Time lag ` = phi/omega = (33.5 pi)/(2pi xx 60 xx 180) = 1.55 ms `