Home
Class 12
PHYSICS
A lamp consumes only 25% of the peak pow...

A lamp consumes only 25% of the peak power in an ac circuit. The phase difference between the applied voltage and the current is

A

a) `pi/6`

B

b) `pi/3`

C

c) `pi/4`

D

d) `pi/2`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • ALTERNATING CURRENT

    NEW JOYTHI PUBLICATION|Exercise PREVIOUS YEAR QUESTIONS|2 Videos
  • ATOMS

    NEW JOYTHI PUBLICATION|Exercise COMPETITIVE EXAM CORNER|5 Videos

Similar Questions

Explore conceptually related problems

An ac voltage is applied to a resistance R and inductor L in series If R and the inductive reactance are both equal to 3Omega the phase difference between the applied voltage and the current in the circuit is :

In a LCR circuit, the voltage across an inductor, capacitor and resitance are 10V, 10V and 30V respectively, what is the phase difference between the applied voltage and the current in the circuit?

Derive an expression for phase angle between the applied voltage and current in a series RLC circuit .

In an electrical circuit, R, I, C and AC voltage source are all connected in series. When L is removed from the circuit, the phase difference between the voltage and current in the circuit, is (pi)/(3). Instead, if C is removed from the circuit, the phase difference is again (pi)/(3). The power factor of the circuit is

In a series RL circuit, the resitance and inductive reactane are the same. Then the phase difference between the voltage and current in the circuit is