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A small candle 2.5 cm in size is placed ...

A small candle 2.5 cm in size is placed at 27 cm in front of a concave mirror of radius of corvature 36 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Describe the nature and size of the image. If the candle is moved closer to the mirror, how would the screen have to be moved ?

Text Solution

Verified by Experts

u = - 27 cm, f = - 18 cm
`(1)/(v) + (1)/(u) = (1)/(f), " " (1)/(-27) + (1)/(v) = (1)/(-18) " " therefore v = (-18 xx 27)/(27 - 18) = - 54` cm
`m = (h_(i))/(h_(0)) = (-v)/(u), (h_(i))/(2.5) = (-(-54))/((-27)) = - 2`
`h_(i) = - 5 ` cm `" " therefore` The image is real, inverted and magnified.
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A small candle 2.5 cm height is placed in front of a concave mirror of radius of curvature 36 cm at a distance 27 cm from the concave mirror. i. At what distance from the mirror should a screen be placed in order to receive a sharp image ? ii. Describe the nature and size of the image. iii. If the candle is moved close to the mirror, what will be the position of the screen ?

An object is placed at a distance of 20.0 cm from a concave mirror of focal length 15.0 cm. (a) What distance from the mirror a screen should be placed to get a sharp image? (b) What is the nature of the image?

Knowledge Check

  • An object 2.5 cm high is placed at a distance of 10 cm from a concave mirror of radius of curvature 30 cm. The size of the image is

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