Wavelength of light in air is `6000Å`. Calculate its wavelength in water(n =4/3) and glass(n= 3/2).

Explanation

Data supplied
`c=3xx10^(8)ms^(-1)," " lamda=6000Å=6000xx10^(-10)m`
Frequency `v=c/(lamda)=(3xx10^(8))/(6000xx10^(-10))=(3xx10^(8))/(6xx10^(-7))=5xx10^(-14)Hz`
In water
`n_(wa)=4/3=c/(c_(w))`
`c_(w)=c/(n_(wa))=(3xx10^(8))/((4//3))=9/4xx10^(8)m//s " " :. lamda_(w)=(c_(w))/v=(9xx10^(8))/(4xx5xx10^(14))=4500Å`
In glass
`n_(ga)=3/2=c/(c_(g))" " :. c_(g)=c/(n_(ga))=(3xx10^(8))/(3//2)=2xx10^(8)m//s`
`:.lamda_(g)=(c_(g))/v=(2xx10^(8))/(5xx10^(14))=4xx10^(-7)=4000Å`