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A star emiting light of wavelength 4500Å...

A star emiting light of wavelength `4500Å` is moving towards the eart with a speed of 3600 km/sec. Determine the wavelength shift and apparent wavelength due to Doppler effect. The speed of light is `3xx10^(8)m//s`

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`v=3.6xx10^(6)m//s, " " lamda=4500xx10^(-10)m" "c=3xx10^(8)m//s`
`Delta lamda=(v lamda)/c` and `Delta lamda=-lamda-lamda.` or `lamda.-lamda`
`:.Delta lamda=(3.6xx10^(6)xx4500xx10^(-10))/(3xx10^(8))=54.00xx10^(-10)m=54Å`
The apparent wavelength `lamda.= Delta -Delta lamda=4446Å`
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