In double slit experiment using light of wavelength 600 nm, the angular width of a fringe formed on a distance screen is `0.1^(@)`. What is the spacing between the two slits?

Explanation

` d sin theta = n lamda`
`d =(n lamda)/( sin theta)=( 1xx600xx10^(-9))/(sin(0.1)^(@))=(6xx10^(-7))/0.0017=3.5xx10^(-4)m`