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Monochromatic light of frequency 6.0xx10...

Monochromatic light of frequency `6.0xx10^(14)Hz` is produced by a laser. The power emitted is `2.0xx10^(-3)`W. (a). What is the energy of a photon in the light beam? (b) How many photons per second, on an average are emitted by the source?

Text Solution

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a. Each photon has an energy
`E=h upsilon=(6.63.10^(-34)Js)(6.0xx10^(14)Hz)=3.98xx10^(-19)J`
b. If N is the number of photons emitted by the source per second, the power P transmitted in the beam equals N times the energy per photon E, so that P = N E. Then
`N=(P)/(E )=(2.0xx10^(-3))/(3.98xx10^(-19))=5.0xx10^(15)` photons per second.
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