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What is the a. momentum, b. speed, and...

What is the
a. momentum, b. speed, and
c. de Broglie wavelength of an electron with kinetic energy of 120 eV.

Text Solution

Verified by Experts

`K_("max")=120eV`
a. `p=sqrt(2meV)=sqrt(2mE_(k))= sqrt(2xx9.1xx10^(-31)xx120 xx 1.6xx10^(-19))=5.9xx10^(-24)kg ms^(-2)`
b. `p=mv`
`v=(p)/(m)=(5.9xx10^(-24))/(9.1xx10^(-31))=6.49xx10^(6)ms^(-1)`
c. `lambda=(h)/(p)=(6.6xx10^(-34))/(5.9xx10^(-24))=0.1186nm`
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