In a parallelogram as shown in the figure `(a != b)` : equation of the diagonal AC is `(a + b) x + (a + b)y = 3 ab`

In a parallelogram as shown in the figure (a!=b): equation of the diagonal AC is (a+b)x+(a+b)y=3ab

In Figure, A B C D is a parallelogram and X\ a n d\ Y are points on the diagonal B D such that D X=B Y . Prove that A X C Y is a parallelogram (ii) A X=C Y ,\ A Y=C X A Y B\ ~= C X D (iv) A X D~=\ C Y B

3x - 2y + 1 = 0 and 2x - y = 0 are the equation of the sides AB and AD of the parallelogram ABCD and the equation of a diagonal of the parallelogram is 5x - 3y - 1 = 0 . The equation of the other diagonal of the parallelogram is : (A) x-y+1=0 (B) x-y-1=0 (C) 3x+5y+13=0 (D) 3x+5y=13

Let ABCD be a parallelogram the equation of whose diagonals are AC : x+2y =3; BD: 2x + y = 3. If length of diagonal AC =4 units and area of ABCD = 8 sq. units. (i) The length of the other diagonal is (ii) the length of side AB is equal to

A diagonal of a parallelogram divides it into two triangles of equal area. GIVEN : A parallelogram A B C D in which B D is one of the diagonals. TO PROVE : ar ( A B D)=a r( C D B)

The two adjacent sides of parallelogram are y =0 and y=sqrt(3)(x-1) .If equation of one diagonal is sqrt(3)y=(x+1), then equation of other diagonal is

3x - 2y + 1 = 0 and 2x - y = 0 are the equation of the sides AB and AD of the parallelogram ABCD and the equation of a diagonal of the parallelogram is 5x - 3y - 1 = 0 . The area of the parallelogram ABCD is : (A) 2 sq. units (B) 4 sq. units (C) 6 sq. units (D) 8 sq. units

3x - 2y + 1 = 0 and 2x - y = 0 are the equation of the sides AB and AD of the parallelogram ABCD and the equation of a diagonal of the parallelogram is 5x - 3y - 1 = 0 . The centroid of DeltaABD is : (A) (1, 4/3) (B) (3, 14/3) (C) (7/3, 10/3) (D) (5/3, 8/3)

a (b+c) = ab + ac is