" 20.यदि "x=a(cos theta+theta sin theta),y=a(sin theta-theta cos theta)," so "(dy)/(dx)" Find out "

If x = a(cos theta + theta sin theta), y = a (sin theta - theta cos theta), (dy)/(dx) =

If x = a(cos theta + theta sin theta), y = a (sintheta - theta cos theta), dy/dx =

If x =a (cos theta +theta sin theta ), y =a (sin theta -theta costheta ) ,then (dy)/(dx) =

If x =a (cos theta + theta sin theta ), y =a (sin theta - theta cos theta ) then (dy)/(dx) =

x = a (cos theta + theta sin theta), y = a (sin theta - theta cos theta) . then find dy/dx

Find dy/dx : x = cos theta + sin theta, y = sin theta - theta cos theta

The normal to the curve x=a(cos theta + theta sin theta), y=a(sin theta - theta cos theta) at any theta is such that