[int(cos2x-cos2 alpha)/(cos x-cos alpha)...

[int(cos2x-cos2 alpha)/(cos x-cos alpha)dx],[quad (NCERT;" A.I."CBSE]

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int(cos2x-cos2alpha)/(cosx-cosalpha)dx

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int(cos2x-cos2 alpha)/(sin x-sin alpha)dx=

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Evaluate: int(cos2x-cos2 alpha)/(cos x-cos alpha)dx

Evaluate: int(cos2x-cos2 alpha)/(cos x-cos alpha)dx

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