[" 23.If "theta" is the angle between the diagonals of a parallelogram "AB],[" vertices are "A(0,2),B(2,-1),C(4,0)" and "D(2,3)" .Show that tan "theta=]

If theta is the angle between the diagonals of a parallelogram ABCD whose vertices are A(0,2),B(2,-1),C(4,0) and D(2,3) Show that tan theta=2

Find the angle between the diagonals of parallelogram ABCD whose vertices are A (0, 2), B (2, - 1), C (4, 0) and D (2, 3).

If theta is the angle between the lines joining the points A(0, 0) and B(2, 3), and the points C(2,-2) and D(3,5), show that tan theta=(11)/(23)

If vertices of a parallelogram are respectively (0,0), (1,0) ,(2,2) and (1,2) then angle between diagonals is

If vertices of a parallelogram are respectively (0,0), (1,0) ,(2,2) and (1,2) then angle between diagonals is

If theta is the angle between the curves xy = 2 and x^(2)+4y = 0 then tan theta =

If theta is the acute angle between the lines 6x^(2)+11xy+3y^(2)=0 ,then tan theta

If veca=(3,1) and vecb=(1,2) represent the sides of a parallelogram then the angle theta between the diagonals of the paralelogram is given by (A) theta=cos^-1(1/sqrt(5)) (B) theta=cos^-1(2/sqrt(5)) (C) theta=cos^-1 (1/(2sqrt(5))) (D) theta = pi/2

If veca=(3,1) and vecb=(1,2) represent the sides of a parallelogram then the angle theta between the diagonals of the paralelogram is given by (A) theta=cos^-1(1/sqrt(5)) (B) theta=cos^-1(2/sqrt(5)) (C) theta=cos^-1 (1/(2sqrt(5))) (D) theta = pi/2