" If "^((n+1))C_(3)=2*^(n)C_(2)," then "n=

If .^(n+1)C_(3)=2(.^(n)C_(2)) , find the value of n.

Find 'n', if ""^(2n)C_(1), ""^(2n)C_(2) and ""^(2n)C_(3) are in A.P.

If ""^(2n)C_(1), ""^(2n)C_(2) and ""^(2n)C_(3) are in A.P., find n.

Find n, if ""^(2n)C_(1),""^(2n)C_(2) and ""^(2n)C_(3) are in A.P.

If \ ^(n+1)C_3=2.\ \ ^n C_2\ t h e n= 3 b. 4 c. 6 d. 5

The value of (""^(n) C_(1)+2. ""^(n) C_(2)+3. ""^(n)C_(3)+…+ n""^(n)C_(n)) is-

STATEMENT - 1 : If n is even, .^(2n)C_(1)+.^(2n)C_(3)+.^(2n)C_(5)+"….."+.^(2n)C_(n-1) = 2^(2n-2) . STATEMENT - 2 : .^(2n)C_(1) + .^(2n)C_(3)+ .^(2n)C_(5) + "……"+ .^(2n)C_(2n-1) = 2^(2n-1)

Solve the inequality .^(n-1)C_4 - .^(n -1)C_3 - 5/4 .^(n-2)C_2 lt 0,n in N