[" If the sum of first in' terms of an "AP" is "cn^(2)" then prove that the "],[" sum of squares of these in' terms is "(nc^(2)(4n^(2)-1))/(3)]

If the sum of first n terms of an A.P. is 3n^(2)-2n , then its 19th term is

If the sum of first n terms of an A.P. is cn^(2) , then the sum of squares of these n terms is :

If the sum of first n terms of an AP is cn^(2) , then the sum of squares of these n terms is (2009)( a) (n(4n^(2)-1)c^(2))/(6) (b) (n(4n^(2)+1)c^(2))/(3) (c) (n(4n^(2)-1)c^(2))/(3) (d) (n(4n^(2)+1)c^(2))/(6)

If the sum of first n terms of an A.P. is cn^(2) then the sum of squares of these n terms is

If the sum of first n terms of an A.P. is cn^(2) then the sum of squares of these n terms is

If the sum of first n terms of an AP is cn^(2) , then the sum of squares of these n terms is

If the sum of first n terms of an AP is cn^(2) , then the sum of squares of these n terms is

In the sum of first n terms of an A.P.is cn^(2), then the sum of squares of these n terms is

The sum of first n terms of an AP is 4n^(2)+2n Find its n th term.