" (ii) "sum_(k=1)^(n)(2^(k)+3^(k-1))

sum_(k=1)^n k^3=

Fill in the blanks: (i) sum_(k=1)^(n)k=1+2+3+……………+n= ………… (ii) sum_(k=1)^(n)k^(2)=1^(2)+2^(2)+3^(2)+………………….+n^(2)= ……………….. (iii) sum_(k=1)^(n)k^(3)=1^(3)+2^(3)+3^(3)+…………..+n^(3)= …………………

sum_(k=1)^(2n+1)(-1)^(k-1)k^(2)=

Evaluate : sum_(k=1)^n (2^k+3^(k-1))

Evaluate : sum_(k=1)^n (2^k+3^(k-1))

Find sum_(k=1)^(n)(1)/(k(k+1)) .

The value of lim_(n rarr oo)sum_(k=1)^(n)(6^(k))/((3^(k)-2^(k))(3^(k+1)-2^(k+1))) is equal to

Let S_(n)=sum_(k=1)^(4n)(-1)^((k(k+1))/2)k^(2) . Then S_(n) can take values