" 20."f(x)={[(sqrt(1+px)-sqrt(1-px))/(x),,-1<=x<0],[(2x+1)/(x-2),,quad 0<=x<=1]

If f(x)={((sqrt(1+px)-sqrt(1-px))/(x) ",", -1 le x lt 0),((2x+1)/(x-2)",", 0 le x le 1):} is continuous in [-1,1] then p is equal to

If f(x)={((sqrt(1+px)-sqrt(1-px))/(x) ",", -1 le x lt 0),((2x+1)/(x-2)",", 0 le x le 1):} is continuous in [-1,1] then p is equal to

f(x)={((sqrt(1+px)-sqrt(1-px))/(x),,,-1 le x lt 0),((2x+1)/(x-2),,,0le x le 1):} is continuous in the interval [-1,1], then p equals :

f(x) = (sqrt(1+px) - sqrt(1 - px))/(x), -1 le x le 0 = (2x + 1)/(x-2), 0 le x le 1 is continuous in the interval [-1, 1], then p is :

If f(x)=(sqrt((1+px))-sqrt((1-px)))/x , -1lex =(2x+1)/(x-2) , 0lexle1 is continuous in the interval [-1,1] . Find P.

f(x)={[(srt(1+px)-sqrt(1-px))/x,-1<=x<0],[(2x+1)/(x-2),0<=x<=1]}is continuous in the interval [-1, 1], then 'p' is equal to:,0

If f(x)=(sqrt((1+px))-sqrt((1-px)))/x , -1lex =(2x+1)/(x-2) , 0lexle1 is continuous in the interval [-1,1] . Find lim_(xrarr0)f(x)