The rate of first order reaction is `0.04 mol L^(-1) s^(-1)` at `10 min` and `0.03 mol L^(-1) s^(-1)` at `20 min` after initiation. Find the half life of the reaction.

The rate of first order reaction is 0.04 mol "L"^(-1)" s"^(-1) at 10 min and 0.03 "mol L"^(-1)" s"^(-1) at 20 min after initiation. Thus, find the half life of the reaction.

In a reaction with initially 0.12 M , the concentration of reactant is reduced to 0.06 M in 10 hour and to 0.03 M in 20 hour. (i) What is order of reaction? (ii) What is rate constant? (b) The rate of a first order reaction is 0.04 mol litre^(-1) s^(-1) at 10 minute and 0.30 mol litre^(-1) at 20 minute after initiation. Find the half-life of the reaction.

the rate of a first - order reaction is 0.04 mol L^(-1) s^(-1) at 10 sec and 0.03 mol L^(-1) S^(-1) at 20 sec after initiation of the reaction the half -life period of the reaction is

The rate of a first order reaction is 0.04 mol L^(-1) s^(-1) after 10 s, and 0.03 mol L^(-1) s^(-1) after 20 s of starting the reaction . Calculate the half- life of the reaction .