`sin^(-1)x+cos^(-1)x,x in[-1,1]=`

tan(sin^(-1)x+cos^(-1)x)

Find the value of sin^(-1)x+cos^(-1)x , when, ∀x in[-1,1]=

The value of x satisfying the equation (sin^(-1)x)^(3)-(cos^(-1)x)^(3)+(sin^(-1)x)(cos^(-1)x)( sin^(-1)x-cos^(-1)x)=(pi^(3))/(16) can not be equal to :

If y=(sin^(-1)x-cos^(-1)x)/(sin^(-1)x+cos^(-1)x)," then "(dy)/(dx)=

prove that sin^(-1)(x)+cos^(-1)(x)=pi/2 , -1<=x<=1

The value of x satisfying the equation (sin^(-1)x)^(3)-(cos^(-1)x)^(3)+(sin^(-1)x)(cos^(-1)x)(sin^(-1)x-cos^(-1)x)=(pi^(3))/(16) is :

If int sin^(-1)x cos^(-1)x dx=f^(-1)(x)[Ax-xf^(-1)(x)-2sqrt(1-x^(2))]+(pi)/(2)sqrt(1-x^(2))+2x+C, then