निम्न सूत्रों को सदिश रूप में लिखिए-
(i) dR = I dL `sintheta`
(ii) `F=qvBsintheta`
(iii) `dB= (mu_(0))/(4pi) (I dl sintheta)/(r^(2))`

The magnetic induction at centre of loop due to current flowing through small element 'dl' is given as dB = mu_(0)/(4pi)(Idl sin theta)/r^(2) where theta is

The magnetic induction at centre of loop due to current flowing through small element 'dl' is given as dB = mu_(0)/(4pi)(Idl sin theta)/r^(2) where theta is

If A=((costheta, 0), (0, costheta)), B=((sintheta, 0), (0, sintheta)] then show that A^(2)+B^(2)=I .

The value of "sin"(45^(@)+ theta)-"cos(45^(@) - theta) is (i) 2costheta (ii) 2sintheta (iii) 1 (iv) 0

The argument of (1+i)/(1-i) is (i) 0 (ii) -(pi)/(2) (iii) (pi)/(2) (iv) pi

If z = (3+isintheta)/(4-icostheta) is purely real and theta in (pi/2,pi) ,then arg(sintheta + i costheta) is -

If z = (3+isintheta)/(4-icostheta) is purely real and theta in (pi/2,pi) ,then arg(sintheta + i costheta) is -

If cot theta=(7)/(8) ,evaluate: (i) ((1+sintheta)(1-sintheta))/((1+costheta)(1-costheta)) (ii) cot^(2)theta

The argument of -I is: (i) pi (ii) -pi (iii) -(pi)/2 (iv) (pi)/2

The magnetic field at the origin due to a current element I vec(dl) placed at position r is (i) ((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3))) -((mu_(0)i)/(4pi))((dvec(l)xxvec(r))/(r^(3))) (iii) ((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3))) -((mu_(0)i)/(4pi))((vec(r)xxdvec(l))/(r^(3)))