In passing `3F` of electricity through three electrolytic cells connect in series containing `Ag^(o+),Ca^(2+),` and `Al^(3+)` ions, respectively. The molar ratio in which the three metal ions are liberated at the electrodes is

On passing 3 faraday of electricity through the three electrolytic cells connected in series containing Ag^+,Ca^(2+) and AI^(3+) ions respectively. The molar ratio in which the three metal ions are liberated at the electrodes is :

On passing 3 faraday of electricity through the three electrolytic cells connected in series containing Ag^+ , Ca^(2+) and Al^(3+) ions respectively. The molar ratio in which the three metal ions are liberated at the electron is

3 faraday electricity was passed through the three electrolytic cells connected in series containing Ag^(+)Ca^(2+) and Al^(+3) ions respectively. The molar ration in which the three metl ions are liberated at the electrodes is :

Three moles of electrons are passed through three solutions in succession containing AgNO_(3),CuSO_(4) and AuCI_(3) respectively. The molar ratio of amounts of cations reduced at cathode will be:-

Three moles of electrons are passed through three solutions in succession containing AgNO_(3),CuSO_(4) and AuCl_(3) respectively. The molar ratio of amounts of cations reduced at cathode will be

Three moles of electrons are passed through three solutions in succession containing AgNO_(3),CuSO_(4) and AuCI_(3) respectively. The molar ratio of amounts of cations reduced at cathode will be:-

If same quantity of electricity is passed through three electrolytic cells containing FeSO_(4),Fe_(2)(SO_(4))_(3) , and Fe(NO_(3))_(3) , then

If same quantity of electricity is passed through three electrolytic cells containing FeSO_(4),Fe_(2)(SO_(4))_(3) , and Fe(NO_(3))_(3) , then