[(cosec A-sin A)(sec A-cos A)=(1)/(tan A+cot A)],[[" Hint : Simplify LHS and RHS separately] "]

Prove the following identity,where the angles involved are acute angles for which the expressions are defined.( ix) (csc A-sin A)(sec A-cos A)=(1)/(tan A+cot A)[ Hint : Simplify L.HS and RHS separately]

Prove the following identity, where the angles involved are acute angles for which the expressions are defined. (ix) (c o s e c\ A\ \ sin\ A)(secA-cosA)=1/(tanA+cotA) [Hint : Simplify LHS and RHS separately]

Prove that: (cosec A-sin A)(sec A-cos A)=(1)/(tan A+cot A)

(cosec x-sin x)(sec x-cos x)(tan x+cot x)=1

(cosec x-sin x)(sec x-cos x)(tan x+cot x)

Prove that ( "cosec" A - sin A)(sec A- cos A)=(1)/((tan A+ cot A)).

Prove that (cosec A - sin A ) (sec A -cos A) = ( 1)/( tan A +cot A)

Prove that (cosec A - sin A ) (sec A -cos A) = ( 1)/( tan A +cot A)

Prove that (cosec A - sin A ) (sec A -cos A) = ( 1)/( tan A +cot A)

Prove that (cosec A - sin A ) (sec A -cos A) = ( 1)/( tan A +cot A)