The circuit showm below constains tow ideal diodes, each with a forward resistance of `50 Omega`. If the battery voltage is 6 V, the current through the `100 Omega` resistance ( in Amperes) is:

The circuit showm below contains two ideal diodes, each with a forward resistance of 50 Omega . If the battery voltage is 6 V, the current through the 100 Omega resistance ( in Amperes) is:

The circuit contains two diodes each with a forward resistance of 50Omega and with infinite reverse resistance. If the battery voltage is 6V, the current through the 120Omega resistance is_ mA

The circuit shown in the figure contains two diodes each with a forward resistance of 50 Omega and with infinite backward resistance. If the battery is 6 V, the current through the 100 Omega resistance (in ampere) is

The circuit shown in figure contains two diodes each with a forward resistance of 50Ω and infinite reverse resistance.If the battery voltage is 6 v ,then the current through the 100Ω resistance is

The circuit shown below contains two diodes, each of forward resistance, 50 Omega and with infinite backward resistance. If the battery voltage is 6V, find the current through 100 Omega resistance.

The circuit shown in the fig. contains two diodes each with forward resistance of 50 Omega and infinite backward resistance. If the battery voltage is 6V, find the current through the 120 Omega resistance.

The circuit shown in the figure contains two diodes each with a forward resistance of 30 Omega and with infinite backward resistance. If the battery is 3 V, the current through the 50 Omega resistance (in ampere) is

The circuit shown in the figure contains two diodes each with a forward resistance of 30 Omega and with infinite backward resistance. If the battery is 3 V, the current through the 50 Omega resistance (in ampere) is