[" 29.In a "/_ABC" ,the sides "],[BC=5,CA=4,AB=3" .If "A(0,0)" and the "],[" internal bisector of angle A meets "BC" in "]

In a /_ABC the sides BC=5,CA=4 and AB=3. If A(0,0) and the internal bisector of angle A meets BC in D((12)/(7),(12)/(7)) then incenter of /_ABC is

In a triangle ABC the sides BC=5, CA=4 and AB=3 . If A(0,0) and the internal bisector of angle A meets BC in D (12/7,12/7) then incenter of triangle ABC is

In a triangle ABC the sides BC=5, CA=4 and AB=3 . If A(0,0) and the internal bisector of angle A meets BC in D (12/7,12/7) then incenter of triangle ABC is

In DeltaABC if A=(0, 0, 4), AB=4, BC=3, CA=5, I=(1,0,1) is the incentre and the internal bisector of angleA intersects BC at D then D_(x )=

In a triangle ABC , AB = AC and angle A = 36^(@) If the internal bisector of angle C meets AB at D . Prove that AD = BC.

Draw a triangle ABC of base BC=5.6 cm, angle A=40^(@) and the bisector of angle A meets BC at D such that CD=4 cm.

The internal bisector of angle A of Delta ABC meets BC at D and the external bisector of angle A meets BC produced at E. Prove that (BD)/(BE) = (CD)/(CE) .

If the incircle of Delta ABC touches the sides BC , CA,AB respectively are D(3,4),E(4,3),F(-3,-4) and the slope of internal bisector of |A is m, then |m|=

In DeltaABC with fixed length of BC , the internal bisector of angle C meets the side AB at D and meet the circumcircle at E. The maximum value of CD xx DE is