Given two circle `x^2+y^2-6x-2y+5=0&x^2+y^2+6x+22 y+5=0` . The tangent at `(2,-1)` to the first circle passes outside the second circle intersects the second circle in 2 real points passes through the centre of the second circle

Consider the following statement in respect of circles x^(2) + y^(2) - 2x - 2 y = 0 and x^(2) +y^(2) = 1 1. The radius of the first circle is twice that of the second circle. 2. Both the circles pass through the origin. Which of the statements given above is/are correct ?

Find the equation of the circle whose centre is at the point (4,5) and which passes through the centre of the circle x^(2)+y^(2)-6x+4y-12=0

If a circle is concentric with the circle x^(2)+y^(2)-4x-6y+9=0 and passes through the point (-4,-5) then its equation is

Equation of the circle with centre at (1,-2) , and passing through the centre of the circle x^(2) + y^(2) + 2y - 3 = 0 , is

A circle passes through the points of intersection of the line x=0 and the circle x^(2)+y^(2)+2x=3. If this circle passes through (sqrt(3),0) then its centre is :

A circle passing through the intersection of the circles x ^(2) + y^(2) + 5x + 4=0 and x ^(2) + y ^(2) + 5y -4 =0 also passes through the origin. The centre of the circle is

The locus of the centres of circles passing through the origin and intersecting the fixed circle x^(2)+y^(2)-5x+3y-1=0 orthogonally is