p^(3)+27=

Suppose E_(1), E_(2), E_(3) be three mutually exclusive events such that P(E_(i))=p_(i)" for " i=1, 2, 3 If p_(1), p_(2), p_(3) are the roots of 27x^(3) -27x^(2)+ax-1=0 the value of a is -

Factorise each of the following : 27p^(3) - (1)/(216)-(9)/(2)p^(2) + (1)/(4)p

if p= log_(6)216 and q = log_(3) 27 then p^(q) = ______

Let p= 3^(1//3) .3^(2//9).3^(3//27) ….oo then p^(1//3) =

Factorize: 27p^(3)-(1)/(216)-(9)/(2)p^(2)+(1)/(4)p

If the roots of the equation x^(3) - px^(2) + qx - r = 0 are in A.P., then prove that, 2p^3 −9pq+27r=0