[" The distance of a point "(2,5,-3)" from the plane "],[bar(r).quad (6bar(i)-3bar(j)+2bar(k))=4" is "]

Find the distance of a point (2,5,-3) form plane bar(r ).(6bar(i) - 3bar(j) + 2bar(k)) = 4 .

Find the distance between the planes bar(r) * ( 2 bar(i) - bar(j) + 3 bar(k)) = 4 and bar(r) * ( 6 bar(i) - 3 bar(j) + 9 bar(k)) + 13 = 0

A point on the line bar(r)=(1-t)(2bar(i)+3bar(j)+4bar(k))+t(3bar(i)-2bar(j)+2bar(k)) is

A point on the line bar(r)=(1-t)(2bar(i)+3bar(j)+4bar(k))+t(3bar(i)-2bar(j)+2bar(k))

bar(r)=2bar(i)+3bar(j)-6bar(k)" then find "abs(bar(r)) .

The distance between the line bar(r)=2bar(i)-2bar(j)+3bar(k)+lambda((bar(i)-bar(j)+4bar(k)) and the plane bar(r).(bar(i)+5bar(j)+bar(k))=5 is

The vector equation of the line joining the points 3bar(i)+2bar(j)-4bar(k), 5bar(i)+4bar(j)-6bar(k) is

If the position vectors of the points A,B,C are -2bar(i)+bar(j)-bar(k), -4bar(i)+2bar(j)+2bar(k), 6bar(i)-3bar(j)-13bar(k) respectively and bar(AB) = lambda bar(AC) then find the value of lambda .

The angle between the planes bar(r)*(2bar(i)-3bar(j)+4bar(k))+11=0 and "bar(r)*(3bar(i)-2bar(j))=0. is