" If "a sec theta+b tan theta=c" then "(a tan theta+b sec theta)^(2)

x =a tan theta ,y =b sec theta

( sec theta + tan theta -1)/( tan theta - sec theta +1)

x = a sec theta, y = b tan theta .

x = a sec theta + b tan theta and y= a tan theta + b sec theta. Prove that x^(2)-y^(2) = a^(2)-b^(2) .

If : sec theta * tan theta (sectheta + tan theta) + (sec theta - tan theta) = sec^(n) theta + tan^(n) theta, "then" : n = A)1 B)2 C)3 D)4

If x=a sec theta+b tan theta and y=a tan theta+b sec theta then prove that x^(2)-y^(2)=a^(2)-b^(2)

If x=a sec theta+b tan theta and y=a tan theta+b sec theta, prove that: x^(2)-y^(2)=a^(2)-b^(2)

The locus of the point of intersection of the lines ax sec theta+by tan theta=a and ax tan theta+by sec theta=b is

if x = a sec theta + b tan theta y = b sec theta + a tan theta then x^(2) - y^(2) is equal to

If sec theta + tan theta = x , then sec theta =