The apparent frequency of a note is 200 Hz when a listener is moving with a velocity of 40 `ms​^(-1)` towards a stationary source. When he moves away from the same source with the same speed, the apparent frequency of the same note is 160 Hz. The velocity of sound in air (in m/s) is :-

The apaarent frequency of a note is 200 Hz when a listener is with a velocity of 40 ms^(-1) towards a stationary source. When he moves away from the same source with the same speed, the apparent frequency of the same note is 160 Hz. The velocity of sound in air in m/s is :

When the listener moves towards a stationary source with a velocity v_(1) m the apparent freqency of a note emitted by the source is f' When the listener moves away from the source with the same velocity, the apparent frequency of the note f/f'=3. If v the velocity of sound in air, the value of v//v_(1) is -

When the listener moves towards a stationary source with a velocity V_(L) , the apparent frequency of a note emitted by the source is f' . When the listener moves away from the source with the same velocity, the apparent frequency of the note is f" . Given f'//f"=3 and V as the velocity of sound in air, the value of V/V_(L) is

A source of sound is moving with a velocity of 50ms^(-1) towards a stationary listener. The listener measures the frequency of the source as 1000Hz. What will be the apparent frequency of the source when it is moving away from the listener after crossing him? (velocity of sound in the medium is 330ms^(-1) ).