`Mn^(2+)` can be converted into `Mn^(7+)` by reacting with

2mNo_(4)^(2-)+cl _(2) rarr Mn^(2+)+5Fe^(3+) MnO_(4)^(2-) can be converted to MnO_(4)^(-)

Between Fe and Mn which can be converted to +2 oxidation state easily ? Given : E_(Fe^(2+)|Fe)^(@) =-0.44" V & "E_(Mn^(2+)|Mn)^(@)= - 1.20 V

Assertion : The highest manganese fluroide is MnF_(4) and the highest oxide is Mn_(2) O_(7) . Reason : In Mn_(2) O_(7) , each Mn is tetrahedrally surrounded by O's including Mn-O-Mn bridge.

2Mn_(2)O_7rarr4MnO_(2)+ 3O_2 (If M is mol. wt. of Mn_(2)O_7 ). Find the equivalent, weight of Mn_2O_7 in the above change.

In acidic medium is converted to Mn2+. The quantity of electricity in faraday required to reduce 0.5 mole MnO_(4)^(-) to Mn^(2+) would be :

In acidic medium is converted to Mn2+. The quantity of electricity in faraday required to reduce 0.5 mole MnO_(4)^(-) to Mn^(2+) would be :