The displacement of a partical as a function of time t is given by `s=alpha+betat+gammat^(2)+deltat^(4)`, where `alpha`,`beta`,`gamma` and `delta` are constants. Find the ratio of the initial velocity to the initial acceleration.

The displacement of particle along a straight line at time t is given by x = 2alpha + betat + gammat^2 . Find its acceleration.

The displacement s of a particle at time t is given by s=alpha sin omegat+beta cos omegat then acceleration at time t is

The equation of displacement for a body at time t is given by x = alphat^3 + betat^2 + gammat + delta . It’s depend upon--

A partical moves along a straight line such that its displacement s=alphat^(3)+betat^(2)+gamma , where t is time and alpha , beta and gamma are constant. Find the initial velocity and the velocity at t=2 .

A partical moves in a straight line as s=alpha(t-2)^(3)+beta(2t-3)^(4) , where alpha and beta are constants. Find velocity and acceleration as a function of time.

The displacement x of a particle varies with time t as x = ae^(-alpha t) + be^(beta t) . Where a,b, alpha and beta positive constant. The velocity of the particle will.

The displacement x of a particle varies with time t as x = ae^(-alpha t) + be^(beta t) . Where a,b, alpha and beta positive constant. The velocity of the particle will.

The displacement x of a particle varies with time t as x = ae^(-alpha t) + be^(beta t) . Where a,b, alpha and beta positive constant. The velocity of the particle will.

The displacement of a particle moving in a straight line is given by the expression x=At^(3)+Bt^(2)+Ct+D in metres, where t is in seconds and A,B,C and D are constant. The ratio between the initial acceleration and initial velocity is

The displacement of a particle moving in a straight line Is given by the expression x = At^(3) + Bt^(2) + Ct + D meters, where t is in seconds and A, B, C and D are constants. The ratio between the initial acceleration and initial velocity is