tan A+2tan2A+4tan4A+8cot8A

Prove the following: tanA+2tan2A+4tan4A+8cot8A=cotA

Prove that : tan A + 2tan2A + 4 tan4A + 8cot8A =cotA

If tan x+2tan2x+4tan4x+8cot8x=sqrt(3) rtehn the general solution of x is

If theta is not an integral multiple of (pi)/(2) , prove that tan theta + 2 tan 2 theta +4 tan 4 theta +8 cot 8 theta = cot theta

(sec 8 A-1)/( sec 4A-1)= ..................... A) (tan 2A)/( tan 8A) B) (tan 8A)/(tan 2A) C) (cot 8A)/(cot 2A) D) (tan 6A)/(tan 2A)

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

(sec8A-1)/(sec4A-1) is equal to (A) (tan2A)/(tan8A) (B) (tan8A)/(tan2A) (C) (cot8A)/(cot2A) (D) none of these

IF tan A + cot A=4 , then tan^4 A + cot ^4 A is equal to

tan theta+2tan2 theta+4cot4 theta=cot theta