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At equilibrium , the concentrations of N...

At equilibrium , the concentrations of `N_(2)=3.0xx10^(-3)M`, `O_(2)=4.2xx10^(-3)M` and `NO=2.8xx10^(-3)M` in a sealed vessel at `800K`. What will be `K_(c)` for the reaction
`N_(2)(g)+O_(2)(g)hArr2NO(g)`

Text Solution

Verified by Experts

For the reaction equilibrium constant, `K_(c)` can be written as,
`K_(c)=([NO]^(2))/([N_(2)][O_(2)])`
`=((2.8xx10^(-3)M)^(2))/((3.0xx10^(-3)M)(4.2xx10^(-3)M))`
`=0.622`
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