Calculate the solubility of `A_(2)X_(2)` in pure water, assuming that neither kind of ion reacts with water. The solubility product of `A_(2)X_(3)`, `K_(sp)=1.1xx10^(-23)`.

Explanation

`A_(2)X_(3)to2A^(3+)+3X^(2-)`
`K_(sp)=[A^(3+)]^(2)[X^(2-)]^(3)=1.1x10^(-23)`
If `S=` solubility of `A_(2)X_(3)`, then
`[A^(3+)]=2S`, `[X^(2-)]=3S`
therefore , `K_(sp)=(2S)^(2)(3S)^(2)=108S^(5)`
`=1.1xx10^(-23)`
thus, `S^(5)=1xx10^(-25)`
`S=1.0xx10^(-5)mol//L`