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At 450K, K(p)=2.0xx10^(10) /bar for the ...

At `450K`, `K_(p)=2.0xx10^(10)` /bar for the given reaction at equilibrium.
`2SO_(2)(g)+O_(2)(g)hArr2SO_(3)(g)`
What is `K_(c)` at this temperature ?

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NCERT TELUGU-EQUILIBRIUM-Exercise
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