Describe the effect of:
a. addition of `H_(2)`
b. addition of `CH_(3)OH`
c. removal of CO
d. removal of `CH_(3)OH` on the equilibrium of the reaction.
`2H_(2)(g)+CO(g)hArrCH_(3)OH(g)`

Decribe the effect of : removal of CO on the equilibrium of the reaction 2H_(2)(g)+CO(g) hArr CH_(3)OH(g)

Decribe the effect of : addition of CH_(3)OH on the equilibrium of the reaction 2H_(2)(g)+CO(g) hArr CH_(3)OH(g)

Write the conversion C_(2) H_(5) OH to CH_(3) COOH

Write the conversion CO , CH_(3) OH to CH_(3) COOH

What is X in the following reaction ? CO + 2H_(2) overset(x ) (to) CH_(3) OH

At 1300K, 0.3 mol of CO ,0.1 mol H_2 , 0.02 mol of H_2O and an unknown amount of CH_4 are present at equilibrium in a vessel. K_c for the reaction CO_(g)+H_2(g) leftrightarrow CH_4(g)+H_2O(g) is 3.9. What is the equilibrium concentration CH_4

The reaction , CO(g)+3H_(2)(g)hArrCH_(4)(g)+H_(2)(g) is at equilibrium at 1300K in a 1L flask. It also contain 0.30 mol of CO , 0.10 mol of H_(2) and 0.02 mol of H_(2)O and an unknown amount of CH_(4) in the flask. Determine the concentration of CH_(4) in the mixture. The equilibrium constant. K_(c) for the reaction at the given temperature is 3.90 .

Calculate the mole fraction of lower alcohol in a mixture of 92g C_(2)H_(5)OH and 32g of CH_(3)OH ?