Home
Class 11
CHEMISTRY
The reaction , CO(g)+3H(2)(g)hArrCH(4)(g...

The reaction , `CO(g)+3H_(2)(g)hArrCH_(4)(g)+H_(2)(g)` is at equilibrium at `1300K` in a `1L` flask. It also contain `0.30` mol of `CO`, `0.10` mol of `H_(2)` and `0.02` mol of `H_(2)O` and an unknown amount of `CH_(4)` in the flask. Determine the concentration of `CH_(4)` in the mixture. The equilibrium constant. `K_(c)` for the reaction at the given temperature is `3.90`.

Promotional Banner

Topper's Solved these Questions

  • EQUILIBRIUM

    NCERT TELUGU|Exercise Exercise|76 Videos
  • ENVIRONMENTAL CHEMISTRY

    NCERT TELUGU|Exercise EXERCISES|20 Videos
  • GASEOUS STATE

    NCERT TELUGU|Exercise QUESTIONS (E. Explain briefly on the following )|10 Videos

Similar Questions

Explore conceptually related problems

At 1300K, 0.3 mol of CO ,0.1 mol H_2 , 0.02 mol of H_2O and an unknown amount of CH_4 are present at equilibrium in a vessel. K_c for the reaction CO_(g)+H_2(g) leftrightarrow CH_4(g)+H_2O(g) is 3.9. What is the equilibrium concentration CH_4

Decribe the effect of : addition of CH_(3)OH on the equilibrium of the reaction 2H_(2)(g)+CO(g) hArr CH_(3)OH(g)

N_(2(g)) + 3H_(2(g)) harr 2NH_(3(g)) is a gaseous phase equilibrium reaction taking place at 400K in a 5 L flask. For this

The equilibrium constant for the reaction , H_(2) (g) + CO_(2) (g) hArr H_(2) O (g) + CO (g) is 16 at 1000^(@) C . If 1.0 mole of H_(2) and 1.0 mole of CO_(2) are placed in one litre flask , the final equilibrium concentration of CO at 1000^(@) C is

The value of K_(c)=4.24 at 800K for the reaction, CO(g)+H_(2)O(g)hArrCO_(2)(g)+H_(2)(g) Calcualte equilibrium concentrations of CO_(2) , H_(2) , CO and H_(2)O at 800K , if only CO and H_(2)O are present initially at concentrations of 0.1M each.

An equilibrium mixture for the reaction, 2H_(2)S(g) hArr 2H_(2) (g) + S_(2) (g) has 1 mole of H_(2) S, 0.2 mole of H_(2) and 0.8 mole of S_(2) in 2 L flask . The value of K_(C) in mol L^(-1) is

NCERT TELUGU-EQUILIBRIUM-Exercise
  1. Predict which of the following reaction will have appreciable concentr...

    Text Solution

    |

  2. The value of K(c) for the reaction 3O(2)(g)hArr2O(3)(g) is 2.0xx10^(-5...

    Text Solution

    |

  3. The reaction , CO(g)+3H(2)(g)hArrCH(4)(g)+H(2)(g) is at equilibrium at...

    Text Solution

    |

  4. What is meant by the conjugate acid-base pair ? Find the conjugate aci...

    Text Solution

    |

  5. Which of the followings are Lewis acids? H(2)O, BF(3), H^(+), and NH(4...

    Text Solution

    |

  6. What will be the conjugate bases of the following Bronsted acids: HF, ...

    Text Solution

    |

  7. Write the conjugate acids for the following Bronsted bases: NH(2)^(-),...

    Text Solution

    |

  8. The species: H(2)O,HCO(3)^(-),HSO(4)^(-) and NH(3) can act both as Bro...

    Text Solution

    |

  9. Explain Lewis acid base theory with suitable example. Classify the fol...

    Text Solution

    |

  10. The concentration of hydrogen ion in a sample of soft drink is 3.8xx10...

    Text Solution

    |

  11. The pH of a sample of vinegar is 3.76. Calculate the concentration of ...

    Text Solution

    |

  12. The ionization constants of HF, H COOH and HCN at 298 K are 6.8x10^(-4...

    Text Solution

    |

  13. The ionization constant of phenol is 1.0xx10^(-10). What is the concen...

    Text Solution

    |

  14. The first ionization constant of H(2)S is 9.1xx10^(-8). Calculate the ...

    Text Solution

    |

  15. The ionization constant of acetic acid is 1.74xx10^(-5). Calculate the...

    Text Solution

    |

  16. It has been found that the pH of a 0.01M soluiton of an organic acid i...

    Text Solution

    |

  17. Assuming complete dissociation, calculate the pH of the following solu...

    Text Solution

    |

  18. Calculate the pH of the following solution : (a) 2g of TlOH dissolve...

    Text Solution

    |

  19. The degree of ionization of a 0.1M bromoacetic acid solution is 0.132....

    Text Solution

    |

  20. The pH of 0.005M codeine (C(18)H(21)NO(3)) solution is 9.95. Calculate...

    Text Solution

    |