Fill in the blanks.

Explanation

Average velocity
`vecv_(avg)=(vecr_(P)-vecr_(O))/(Deltat)`
Here `Deltat=5s`
`vecr_(0)=0,vecr_(P)=10hati`
`vecv_(avg)=(10hati)/(5sec)=2haticms^(-1)`
The average velocity is in the positive x direction.
The average speed =total path length / time taken (the path is semi-circular)
`=(5picm)/(5s)=picms^(-1)~~3.14cms^(-1)`
For the mass of 1 kg
`p=1xx10=10kgms^(-1)`
Thus even though both the masses have the same speed, the momentum of the heavier mass is 100 times greater than that of the lighter mass.