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In the cricket game, a batsman strikes t...

In the cricket game, a batsman strikes the ball such that it moves with the speed `30ms^(-1)` at an angle `30^(@)` with the horizontal as shown in the figure. The boundary line of the cricket ground is located at a distance of 75 m from the batsman? Will the ball go for a six? (Neglect the air resistance and take acceleration due to gravity `g=10ms^(-2)`.

Text Solution

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The motion of the cricket ball in air is essentially a projectile motion. As we have already seen, the range (horizontal distance) of the projectile motion is given by
`R=(u^(2)sin2theta)/(g)`
The initial speed `u=30ms^(-1)`
The projection angle `theta=30^(@)`
The horizontal distance travelled by the cricket ball
`R=((30)^(2)xxsin60^(@))/(10)=(900xx(sqrt3)/(2))/(10)=77.94m`
This distance is greater than the distance of the boundary line. Hence the ball will cross this line and go for a six.
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